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प्रश्न
By remainder theorem, find the remainder when, p(x) is divided by g(x) where, p(x) = x3 – 2x2 – 4x – 1; g(x) = x + 1
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उत्तर
p(x) = x3 – 2x2 – 4x – 1, g(x) = x + 1
Let g(x) = x + 1
x + 1 = 0
x = –1
p(x) = x3 – 2x2 – 4x – 1
p(–1) = (–1)3 – 2(– 1)2 – 4(–1) – 1
= –1 – 2 × 1 + 4 – 1
= –4 – 4 = 0
∴ Remainder = 0.
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