Advertisements
Advertisements
Question
Find the first term and common difference for the A.P.
127, 135, 143, 151,...
Advertisements
Solution
127, 135, 143, 151,...
First term = 127
Common difference = Second term – First term
= 135 – 127
= 8
APPEARS IN
RELATED QUESTIONS
Determine the A.P. whose 3rd term is 16 and the 7th term exceeds the 5th term by 12.
Show that a1, a2,..., an... form an AP where an is defined as below:
an = 3 + 4n
Also, find the sum of the first 15 terms.
If the sum of first m terms of an A.P. is the same as the sum of its first n terms, show that the sum of its first (m + n) terms is zero
Find the sum of the following arithmetic progressions:
41, 36, 31, ... to 12 terms
How many two-digits numbers are divisible by 3?
Find the sum of first n terms of an AP whose nth term is (5 – 6n). Hence, find the sum of its first 20 terms.
Find the first term and common difference for the following A.P.:
5, 1, –3, –7, ...
If m times the mth term of an A.P. is eqaul to n times nth term then show that the (m + n)th term of the A.P. is zero.
Rs 1000 is invested at 10 percent simple interest. Check at the end of every year if the total interest amount is in A.P. If this is an A.P. then find interest amount after 20 years. For this complete the following activity.
The sum of first seven terms of an A.P. is 182. If its 4th and the 17th terms are in the ratio 1 : 5, find the A.P.
The sum of the first n terms of an A.P. is 3n2 + 6n. Find the nth term of this A.P.
Write the common difference of an A.P. whose nth term is an = 3n + 7.
If k, 2k − 1 and 2k + 1 are three consecutive terms of an A.P., the value of k is
Suppose three parts of 207 are (a − d), a , (a + d) such that , (a + d) >a > (a − d).
Find the sum of the first 10 multiples of 6.
If an = 3 – 4n, show that a1, a2, a3,... form an AP. Also find S20.
The sum of the first 15 multiples of 8 is ______.
The first term of an AP is –5 and the last term is 45. If the sum of the terms of the AP is 120, then find the number of terms and the common difference.
In an A.P., if Sn = 3n2 + 5n and ak = 164, find the value of k.
If the first term of an A.P. is 5, the last term is 15 and the sum of first n terms is 30, then find the value of n.
