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Maharashtra State BoardSSC (English Medium) 10th Standard

Rs 1000 is invested at 10 percent simple interest. Check at the end of every year if the total interest amount is in A.P. If this is an A.P. then find interest amount after 20 years.

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Question

Rs 1000 is invested at 10 percent simple interest. Check at the end of every year if the total interest amount is in A.P. If this is an A.P. then find interest amount after 20 years. For this complete the following activity.

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Solution

It is given that,
Principal (P) = Rs 1000
Rate (R) = 10%
Simple interest (S.I.) =\[\frac{P \times R \times T}{100}\]

Simple interest after an year = \[\frac{1000 \times 10 \times 1}{100} = Rs 100\]

Simple interest after 2 years = \[\frac{1000 \times 10 \times 2}{100} = Rs 200\]

Simple interest after 3 years = \[\frac{1000 \times 10 \times 3}{100} = Rs 300\]

Hence, the total interest amount is in A.P. i.e. 100, 200, 300,....

Here,
a = 100
d = 100
Now,

\[a_n = a + \left( n - 1 \right)d\]

\[ a_{20} = a + \left( 20 - 1 \right)d\]

\[ = 100 + 19\left( 100 \right)\]

\[ = 100 + 1900\]

\[ = 2000\]

Hence, the interest amount after 20 years is Rs 2000.

 
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Chapter 3: Arithmetic Progression - Problem Set 3 [Page 80]

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Balbharati Algebra Mathematics 1 [English] Standard 10 Maharashtra State Board
Chapter 3 Arithmetic Progression
Problem Set 3 | Q 14 | Page 80

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