मराठी
महाराष्ट्र राज्य शिक्षण मंडळएस.एस.सी (इंग्रजी माध्यम) इयत्ता १० वी

Rs 1000 is invested at 10 percent simple interest. Check at the end of every year if the total interest amount is in A.P. If this is an A.P. then find interest amount after 20 years.

Advertisements
Advertisements

प्रश्न

Rs 1000 is invested at 10 percent simple interest. Check at the end of every year if the total interest amount is in A.P. If this is an A.P. then find interest amount after 20 years. For this complete the following activity.

Advertisements

उत्तर

It is given that,
Principal (P) = Rs 1000
Rate (R) = 10%
Simple interest (S.I.) =\[\frac{P \times R \times T}{100}\]

Simple interest after an year = \[\frac{1000 \times 10 \times 1}{100} = Rs 100\]

Simple interest after 2 years = \[\frac{1000 \times 10 \times 2}{100} = Rs 200\]

Simple interest after 3 years = \[\frac{1000 \times 10 \times 3}{100} = Rs 300\]

Hence, the total interest amount is in A.P. i.e. 100, 200, 300,....

Here,
a = 100
d = 100
Now,

\[a_n = a + \left( n - 1 \right)d\]

\[ a_{20} = a + \left( 20 - 1 \right)d\]

\[ = 100 + 19\left( 100 \right)\]

\[ = 100 + 1900\]

\[ = 2000\]

Hence, the interest amount after 20 years is Rs 2000.

 
shaalaa.com
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 3: Arithmetic Progression - Problem Set 3 [पृष्ठ ८०]

APPEARS IN

बालभारती Algebra Mathematics 1 [English] Standard 10 Maharashtra State Board
पाठ 3 Arithmetic Progression
Problem Set 3 | Q 14 | पृष्ठ ८०

संबंधित प्रश्‍न

If Sn1 denotes the sum of first n terms of an A.P., prove that S12 = 3(S8 − S4).


Find the sum of the following APs:

2, 7, 12, ..., to 10 terms.


Find the sum given below:

–5 + (–8) + (–11) + ... + (–230)


The first term of an A.P. is 5, the last term is 45 and the sum is 400. Find the number of terms and the common difference.


Find the sum of the first 11 terms of the A.P : 2, 6, 10, 14, ...


Find the sum 2 + 4 + 6 ... + 200


If the 10th term of an AP is 52 and 17th term is 20 more than its 13th  term, find the AP.


The 9th term of an AP is –32 and the sum of its 11th and 13th terms is –94. Find the common difference of the AP. 


The 19th term of an AP is equal to 3 times its 6th term. If its 9th term is 19, find the AP.


If an denotes the nth term of the AP 2, 7, 12, 17, ..., find the value of (a30 - a20).


Find the sum of the following APs:

9, 7, 5, 3, ... to 14 terms.


Simplify `sqrt(50)`


Find the sum:  1 + 3 + 5 + 7 + ... + 199 .


The sum of the first n terms of an A.P. is 4n2 + 2n. Find the nth term of this A.P. 


Which term of the sequence 114, 109, 104, ... is the first negative term?

 

The first and last term of an A.P. are a and l respectively. If S is the sum of all the terms of the A.P. and the common difference is given by \[\frac{l^2 - a^2}{k - (l + a)}\] , then k =

 

 


If the first term of an A.P. is a and nth term is b, then its common difference is


The middle most term(s) of the AP: -11, -7, -3,.... 49 is ______.


If the first term of an A.P. is p, second term is q and last term is r, then show that sum of all terms is `(q + r - 2p) xx ((p + r))/(2(q - p))`.


The sum of 40 terms of the A.P. 7 + 10 + 13 + 16 + .......... is ______.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×