Advertisements
Advertisements
प्रश्न
Find how many integers between 200 and 500 are divisible by 8.
Advertisements
उत्तर
First term between 200 and 500 divisible by 8 is 208, and the last term is 496.
So, first term (a) = 208
Common difference (d) = 8
an = a + (n − 1)d = 496
⇒208 + (n − 1)8 = 496
⇒(n−1)8 = 288
⇒ n − 1 = 36
⇒n=37
Hence, there are 37 integers between 200 and 500 which are divisible by 8.
APPEARS IN
संबंधित प्रश्न
Find the sum of first 12 natural numbers each of which is a multiple of 7.
For what value of p are 2p + 1, 13, 5p − 3 are three consecutive terms of an A.P.?
If the sum of n terms of an A.P. is 3n2 + 5n then which of its terms is 164?
If Sn denote the sum of the first n terms of an A.P. If S2n = 3Sn, then S3n : Sn is equal to
If \[\frac{1}{x + 2}, \frac{1}{x + 3}, \frac{1}{x + 5}\] are in A.P. Then, x =
The sum of n terms of an A.P. is 3n2 + 5n, then 164 is its
If 18th and 11th term of an A.P. are in the ratio 3 : 2, then its 21st and 5th terms are in the ratio
The common difference of the A.P. is \[\frac{1}{2q}, \frac{1 - 2q}{2q}, \frac{1 - 4q}{2q}, . . .\] is
In an A.P., if Sn = 3n2 + 5n and ak = 164, find the value of k.
Find the sum of those integers from 1 to 500 which are multiples of 2 as well as of 5.
