Advertisements
Advertisements
प्रश्न
Find how many integers between 200 and 500 are divisible by 8.
Advertisements
उत्तर
First term between 200 and 500 divisible by 8 is 208, and the last term is 496.
So, first term (a) = 208
Common difference (d) = 8
an = a + (n − 1)d = 496
⇒208 + (n − 1)8 = 496
⇒(n−1)8 = 288
⇒ n − 1 = 36
⇒n=37
Hence, there are 37 integers between 200 and 500 which are divisible by 8.
APPEARS IN
संबंधित प्रश्न
In an A.P. the first term is 25, nth term is –17 and the sum of n terms is 132. Find n and the common difference.
The 4th term of an AP is zero. Prove that its 25th term is triple its 11th term.
The 24th term of an AP is twice its 10th term. Show that its 72nd term is 4 times its 15th term.
Find the sum of first n even natural numbers.
What is the sum of first 10 terms of the A. P. 15,10,5,........?
Write the common difference of an A.P. whose nth term is an = 3n + 7.
If 18th and 11th term of an A.P. are in the ratio 3 : 2, then its 21st and 5th terms are in the ratio
A manufacturer of TV sets produces 600 units in the third year and 700 units in the 7th year. Assuming that the production increases uniformly by a fixed number every year, find:
- the production in the first year.
- the production in the 10th year.
- the total production in 7 years.
Q.2
First four terms of the sequence an = 2n + 3 are ______.
