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First term and the common differences of an A.P. are 6 and 3 respectively; find S27. Solution: First term = a = 6, common difference = d = 3, S27 = ? - Algebra Mathematics 1

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Question

First term and the common differences of an A.P. are 6 and 3 respectively; find S27.

Solution: First term = a = 6, common difference = d = 3, S27 = ?

Sn = `"n"/2 [square + ("n" - 1)"d"]` - Formula

Sn = `27/2 [12 + (27 - 1)square]`

= `27/2 xx square`

= 27 × 45

S27 = `square`

Sum
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Solution

It is given that,

First term (a) = 6

Common difference (d) = 3 

Sn = `n/2 [bb(2a) + (n - 1)d]` - Formula

∴ S27 = `27/2 [2(6) + (27 - 1)bb((3))]`

= `27/2 (12 + 26 (3))`

= `27/2 (12 + 78)`

= `27/2 xx bb90`

= 1215

Hence, S27 = 1215.

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Chapter 3: Arithmetic Progression - Practice Set 3.3 [Page 72]

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Balbharati Algebra (Mathematics 1) [English] Standard 10 Maharashtra State Board
Chapter 3 Arithmetic Progression
Practice Set 3.3 | Q 1 | Page 72

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