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Question
Which term of the AP ` 5/6 , 1 , 1 1/6 , 1 1/3` , ................ is 3 ?
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Solution
In the given AP, first term =`5/6 "and common difference" , d = (1-5/6 = 1/6)`
Let its nth term be 3.
Now, Tn = 3
⇒ a + (n-1) d = 3
⇒ `5/6 + (n-1) xx 1/6 = 3`
⇒`2/3 + n/6 =3`
⇒`n/6 = 7/3`
⇒ n= 14
Hence, the 14th term of the given AP is 3.
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