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Question
Find the distance of the point whose position vector is `(2hati + hatj - hatk)` from the plane `vecr * (hati - 2hatj + 4hatk)` = 9
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Solution
Here `veca = 2hati + hatj - hatk`
`vecn = hati - 2hatj + 4hatk`
And d = 9
So, the required distance is `(|(2hati + hatj - hatk)*(hati - 2hatj + 4hatk) - 9|)/sqrt(1 + 4 + 16)`
= `(|2 - 2 - 4 - 9|)/sqrt(21)`
= `13/sqrt(21)`.
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