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Question
Find the distance between parallel lines:
15x + 8y – 34 = 0 and 15x + 8y + 31 = 0
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Solution
We know that the distance between two parallel lines = `|("C"_1 ∼ "C"_2)/(sqrt("a"^2 + "b"^2))|`
Here, C1 = −34, C2 = 31
a = 15, b = 8
∴ Distance between given parallel lines = `|(-34 - 31)/sqrt(15^2 + 8^2)|`
= `65/sqrt(225 + 64)`
= `65/sqrt(289)`
= `65/17` units
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