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The distance between the parallel lines 3x โˆ’ 4y + 7 = 0 and 3x โˆ’ 4y + 5 = 0 is ๐‘Ž๐‘. Value of a + b is ______.

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Question

The distance between the parallel lines 3x − 4y + 7 = 0 and 3x − 4y + 5 = 0 is `a/b`. Value of a + b is ______.

Options

  • 2

  • 5

  • 7

  • 3

MCQ
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Solution

The distance between the parallel lines 3x − 4y + 7 = 0 and 3x − 4y + 5 = 0 is `a/b`. Value of a + b is 7.

Explanation:

Given parallel lines are

3x − 4y + 7 = 0 and 3x − 4y + 5 = 0

Required distance = `|7 − 5|/(sqrt((3)^2 + (−4)^2)) = 2/5`

⇒ a = 2, b = 5

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