Question

The distance between the parallel lines 3x − 4y + 7 = 0 and 3x − 4y + 5 = 0 is `a/b`. Value of a + b is ______.

पर्याय

• 2

• 5

• 7

• 3

Answer 1

The distance between the parallel lines 3x − 4y + 7 = 0 and 3x − 4y + 5 = 0 is `a/b`. Value of a + b is 7.

Explanation:

Given parallel lines are

3x − 4y + 7 = 0 and 3x − 4y + 5 = 0

Required distance = `|7 − 5|/(sqrt((3)^2 + (−4)^2)) = 2/5`

⇒ a = 2, b = 5