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Question
Find the area of triangle whose vertices are
`"P"(3/2, 1), "Q"(4, 2), "R"(4, (-1)/2)`
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Solution
Given: `"P"(3/2, 1), "Q"(4, 2), "R"(4, (-1)/2)`
∴ area of ΔPQR = `1/2|(3/2, 1, 1),(4, 2, 1),(4, -1/2, 1)|`
= `1/2[3/2(2 + 1/2) - 1(4 - 4) + 1(-2 - 8)]`
= `1/2(15/4 - 0 - 10)`
= `1/2(-25/4)`
= `-25/8`
As the area cannot be negative,
area of ΔPQR = `25/8` sq. units
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