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Question
Find the area enclosed by the following figure:
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Solution
The given shape contains a semi-circle and a triangle.
Area of semi-circle
= `1/2 πr^2`
= `1/2 xx 22/7 xx 10 xx 10`
= `1100/7`cm2
Area of triangle
= `1/2` × Base × Height
= `1/2 xx 20 xx 7`
= 70 cm2
Hence, total area enclosed by the shape
= `1100/7 + 70`
= `(1100 + 490)/7`
= `1590/7`
= 227 cm2 (approx)
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