Advertisements
Advertisements
प्रश्न
Find the area enclosed by the following figure:

Advertisements
उत्तर

The given shape contains a semi-circle and a triangle.
Area of semi-circle
= `1/2 πr^2`
= `1/2 xx 22/7 xx 10 xx 10`
= `1100/7`cm2
Area of triangle
= `1/2` × Base × Height
= `1/2 xx 20 xx 7`
= 70 cm2
Hence, total area enclosed by the shape
= `1100/7 + 70`
= `(1100 + 490)/7`
= `1590/7`
= 227 cm2 (approx)
APPEARS IN
संबंधित प्रश्न
A 3 m wide path runs outside and around a rectangular park of length 125 m and breadth 65 m. Find the area of the path.
A verandah of width 2.25 m is constructed all along outside a room which is 5.5 m long and 4 m wide. Find:
1) the area of the verandah
2) the cost of cementing the floor of the verandah at the rate of Rs 200 per m2.
In the following figure, find the area of the shaded portions

In the following figure, find the area of the shaded portions

Find the area of the quadrilateral ABCD.
Here, AC = 22 cm, BM = 3 cm,
DN = 3 cm, and
BM⊥AC, DN⊥AC

A path 5 m wide runs along inside a square park of side 100 m. Find the area of the path. Also, find the cost of cementing it at the rate of Rs. 250 per 10 m2.
Find the area enclosed by the following figure:

Find the area enclosed by the following figure:

A floor is 5 m long and 4 m wide. A square carpet with sides of 3 m is laid on the floor. What is the area of the floor that is not carpeted?
If the area of a rectangle is 45 cm² and its breadth is 10 cm, what is the length of the rectangle?
