Advertisements
Advertisements
प्रश्न
A verandah of width 2.25 m is constructed all along outside a room which is 5.5 m long and 4 m wide. Find:
1) the area of the verandah
2) the cost of cementing the floor of the verandah at the rate of Rs 200 per m2.
Advertisements
उत्तर

1)
Length (l) of room = 5.5 m
Breadth (b) of room = 4 m
Area of room = l × b = 5.5 × 4 = 22 m2
From the figure, it can be observed that the new length and breadth of the room, when verandah is also included, are 10 m and 8.5 m respectively.
Area of the room including the verandah = 10 × 8.5 = 85 m2
Area of verandah = Area of the room including the verandah − Area of room
= 85 − 22 = 63 m2
2)
Cost of cementing 1 m2 area of the floor of the verandah = Rs 200
Cost of cementing 63 m2 area of the floor of the verandah = 200 × 63
= Rs 12600
संबंधित प्रश्न
A picture is painted on a cardboard 8 cm long and 5 cm wide such that there is a margin of 1.5 cm along each of its sides. Find the total area of the margin.
In the following figure, find the area of the shaded portions

Find the area of the quadrilateral ABCD.
Here, AC = 22 cm, BM = 3 cm,
DN = 3 cm, and
BM⊥AC, DN⊥AC

Two crossroads, each of width 5 m, run at right angles through the center of a rectangular park of length 70 m and breadth 45 m and parallel to its sides. Find the area of the roads. Also, find the cost of constructing the roads at a rate of Rs. 105 per m2.
Find the area enclosed by the following figure:

Find the area enclosed by the following figure:

Find the area enclosed by the following figure:

If the area of a rectangle is 45 cm² and its breadth is 10 cm, what is the length of the rectangle?
The cost of flooring a room at ₹68 per square meter is ₹2040. If the length of the room is 7.5 m, what is the breadth?
The perimeter of a square plot is 200 m. What is the area of the plot?
