Advertisements
Advertisements
प्रश्न
A verandah of width 2.25 m is constructed all along outside a room which is 5.5 m long and 4 m wide. Find:
1) the area of the verandah
2) the cost of cementing the floor of the verandah at the rate of Rs 200 per m2.
Advertisements
उत्तर
1)
Length (l) of room = 5.5 m
Breadth (b) of room = 4 m
Area of room = l × b = 5.5 × 4 = 22 m2
From the figure, it can be observed that the new length and breadth of the room, when verandah is also included, are 10 m and 8.5 m respectively.
Area of the room including the verandah = 10 × 8.5 = 85 m2
Area of verandah = Area of the room including the verandah − Area of room
= 85 − 22 = 63 m2
2)
Cost of cementing 1 m2 area of the floor of the verandah = Rs 200
Cost of cementing 63 m2 area of the floor of the verandah = 200 × 63
= Rs 12600
संबंधित प्रश्न
A picture is painted on a cardboard 8 cm long and 5 cm wide such that there is a margin of 1.5 cm along each of its sides. Find the total area of the margin.
Pragya wrapped a cord around a circular pipe of radius 4 cm (adjoining figure) and cut off the length required of the cord. Then she wrapped it around a square box of side 4 cm (also shown). Did she have any cord left? (π= 3.14)
In the following figure, find the area of the shaded portions
Find the area of the quadrilateral ABCD.
Here, AC = 22 cm, BM = 3 cm,
DN = 3 cm, and
BM⊥AC, DN⊥AC
A path 5 m wide runs along inside a square park of side 100 m. Find the area of the path. Also, find the cost of cementing it at the rate of Rs. 250 per 10 m2.
Find the area enclosed by the following figure:
Find the area enclosed by the following figure:
A floor is 5 m long and 4 m wide. A square carpet with sides of 3 m is laid on the floor. What is the area of the floor that is not carpeted?
If the area of a rectangle is 45 cm² and its breadth is 10 cm, what is the length of the rectangle?
The perimeter of a square plot is 200 m. What is the area of the plot?
