Advertisements
Advertisements
प्रश्न
Find the area enclosed by the following figure:
Advertisements
उत्तर
The given shape has a triangle and a rectangle.
For rectangle, l = 13 cm and b = 4 cm
∴ Area of rectangle = l × b = 13 × 4 = 52 cm2
For triangle, base (b) = 5 cm
And height (h) = (16 – 4) cm = 12 cm
∴ Area of triangle = `1/2` × b × h = `1/2` × 5 × 12 = 30 cm2
∴ Total area enclosed by the shape = (52 + 30) cm2 = 82 cm2
APPEARS IN
संबंधित प्रश्न
A 3 m wide path runs outside and around a rectangular park of length 125 m and breadth 65 m. Find the area of the path.
A verandah of width 2.25 m is constructed all along outside a room which is 5.5 m long and 4 m wide. Find:
1) the area of the verandah
2) the cost of cementing the floor of the verandah at the rate of Rs 200 per m2.
A path 1 m wide is built along the border and inside a square garden of side 30 m. Find:
1) the area of the path
2) the cost of planting grass in the remaining portion of the garden at the rate of Rs 40 per m2
The adjoining figure represents a rectangular lawn with a circular flower bed in the
middle. Find:
1) the area of the whole land
2) the area of the flower bed
3) the area of the lawn excluding the area of the flower bed
4) the circumference of the flower bed.
In the following figure, find the area of the shaded portions
Find the area of the quadrilateral ABCD.
Here, AC = 22 cm, BM = 3 cm,
DN = 3 cm, and
BM⊥AC, DN⊥AC
Find the area enclosed by the following figure:
Find the area enclosed by the following figure:
If the area of a rectangle is 45 cm² and its breadth is 10 cm, what is the length of the rectangle?
The cost of flooring a room at ₹68 per square meter is ₹2040. If the length of the room is 7.5 m, what is the breadth?
