Advertisements
Advertisements
प्रश्न
Find the area enclosed by the following figure:
Advertisements
उत्तर
The given shape has a triangle and a rectangle.
For rectangle, l = 13 cm and b = 4 cm
∴ Area of rectangle = l × b = 13 × 4 = 52 cm2
For triangle, base (b) = 5 cm
And height (h) = (16 – 4) cm = 12 cm
∴ Area of triangle = `1/2` × b × h = `1/2` × 5 × 12 = 30 cm2
∴ Total area enclosed by the shape = (52 + 30) cm2 = 82 cm2
APPEARS IN
संबंधित प्रश्न
A path 1 m wide is built along the border and inside a square garden of side 30 m. Find:
1) the area of the path
2) the cost of planting grass in the remaining portion of the garden at the rate of Rs 40 per m2
In the following figure, find the area of the shaded portions
In the following figure, find the area of the shaded portions
Find the area of the quadrilateral ABCD.
Here, AC = 22 cm, BM = 3 cm,
DN = 3 cm, and
BM⊥AC, DN⊥AC
A rectangular park is 45 m long and 30 m wide. A path 2.5 m wide is constructed outside the park. Find the area of the path.
Two crossroads, each of width 5 m, run at right angles through the center of a rectangular park of length 70 m and breadth 45 m and parallel to its sides. Find the area of the roads. Also, find the cost of constructing the roads at a rate of Rs. 105 per m2.
Find the area enclosed by the following figure:
Find the area enclosed by the following figure:
The perimeter of a square field is 112 m. What is the area of the square field?
The perimeter of a square plot is 200 m. What is the area of the plot?
