Advertisements
Advertisements
प्रश्न
Find the area enclosed by the following figure:

Advertisements
उत्तर
The given shape contains a rectangle and a semi-circle.
∴ Area of rectangle = l × b = (10.2 × 1.5) cm2 = 15.3 cm2
Here, Diameter of semi-circle = (10.2 – 3.9) cm = 6.3 cm
So, radius = `"Diameter"/2 = 6.3/2` = 3.15 cm
∴ Area of semi-circle = `1/2 πr^2` = `22/7 xx 1/2 xx 3.15 xx 3.15` = 15.59 cm2
∴ Total area = Area of rectangle + Area of semi-circle = 15.3 + 15.59 = 30.89 cm2
APPEARS IN
संबंधित प्रश्न
A 3 m wide path runs outside and around a rectangular park of length 125 m and breadth 65 m. Find the area of the path.
A verandah of width 2.25 m is constructed all along outside a room which is 5.5 m long and 4 m wide. Find:
1) the area of the verandah
2) the cost of cementing the floor of the verandah at the rate of Rs 200 per m2.
Find the area of the quadrilateral ABCD.
Here, AC = 22 cm, BM = 3 cm,
DN = 3 cm, and
BM⊥AC, DN⊥AC

Find the area enclosed by the following figure:

Find the area enclosed by the following figure:

A floor is 5 m long and 4 m wide. A square carpet with sides of 3 m is laid on the floor. What is the area of the floor that is not carpeted?
If the area of a rectangle is 45 cm² and its breadth is 10 cm, what is the length of the rectangle?
The perimeter of a square field is 112 m. What is the area of the square field?
The cost of flooring a room at ₹68 per square meter is ₹2040. If the length of the room is 7.5 m, what is the breadth?
The perimeter of a square plot is 200 m. What is the area of the plot?
