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Question
Find the area enclosed by the following figure:
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Solution
The given shape contains a rectangle and a triangle.
For rectangle, l = 15 m and b = 3 cm
∴ Area of rectangle = l × b = 15 × 3 = 45 cm2
According to the figure,
BE = AB – AE = 15 – 10 = 5 cm
For triangle, base (b) = BE = 5 cm and height (h) = 4 cm
∴ Area of ΔBEG = `1/2` × b × h = `1/2` × 5 × 4 = 10 cm2
∴ Total area enclosed by the shape = (45 + 10) cm2 = 55 cm2.
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