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Find the Particular Solution of the Differential Equation D Y D X = − 4 X Y 2 Given that Y = 1, When X = 0.

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Question

Find the particular solution of the differential equation \[\frac{dy}{dx} = - 4x y^2\] given that y = 1, when x = 0.

Sum
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Solution

We have,

\[\frac{dy}{dx} = - 4x y^2 \]

\[ \Rightarrow \frac{1}{y^2}dy = - 4x dx\]

Integrating both sides, we get

\[\int\frac{1}{y^2}dy = - 4\int x dx\]

\[ \Rightarrow \frac{- 1}{y} = - 2 x^2 + C . . . . . \left( 1 \right)\]

Now,

When `x = 0, y = 1`

\[ \therefore - 1 = 0 + C\]

\[ \Rightarrow C = - 1\]

Putting the value of `C` in (1), we get

\[\frac{- 1}{y} = - 2 x^2 - 1\]

\[ \Rightarrow \frac{1}{y} = 2 x^2 + 1\]

\[ \Rightarrow y = \frac{1}{2 x^2 + 1}\]

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Chapter 21: Differential Equations - Revision Exercise [Page 146]

APPEARS IN

R.D. Sharma Mathematics Volume 1 and 2 [English] Class 12
Chapter 21 Differential Equations
Revision Exercise | Q 63 | Page 146

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