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Karnataka Board PUCPUC Science Class 11

Find out the oxidation number of chlorine in the following compounds and arrange them in increasing order of oxidation number of chlorine. [\ce{NaClO4, NaClO3, NaClO, KClO2, Cl2O7, ClO3, Cl2O, NaCl

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Question

Find out the oxidation number of chlorine in the following compounds and arrange them in increasing order of oxidation number of chlorine.

\[\ce{NaClO4, NaClO3, NaClO, KClO2, Cl2O7, ClO3, Cl2O, NaCl, Cl2 , ClO2}\].

Which oxidation state is not present in any of the above compounds?

Long Answer
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Solution

We can calculate the oxidation states by:

\[\ce{NaClO4}\] Oxidation no. of chlorine = +7 

Suppose oxidation number of chlorine is x then, 1 + x + 4 × (−2) = 0

∴ x – 7 = 0 

x = +7

We can calculate, the oxidation states, as given below:

\[\ce{NaClO3}\] Oxidation no. of chlorine = +5

\[\ce{​NaClO}\] Oxidation no. of chlorine = +1

\[\ce{​KClO2}\] Oxidation no. of chlorine = +3

​\[\ce{Cl2O7}\] Oxidation no. of chlorine = +7

\[\ce{ClO3}\] Oxidation no. of chlorine = +6

\[\ce{Cl2O}\] Oxidation no. of chlorine = +1 

\[\ce{NaCl}\] Oxidation no. of chlorine = −1

\[\ce{Cl2}\] Oxidation no. of chlorine = 0

\[\ce{ClO2}\] Oxidation no. of chlorine = +4.

Oxidation state (+2) is not present in any of the above compounds.

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Chapter 8: Redox Reactions - Multiple Choice Questions (Type - I) [Page 110]

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NCERT Exemplar Chemistry [English] Class 11
Chapter 8 Redox Reactions
Multiple Choice Questions (Type - I) | Q 37 | Page 110

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