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Karnataka Board PUCPUC Science Class 11

Identify disproportionation reaction - Chemistry

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Question

Identify disproportionation reaction

Options

  • \[\ce{CH4 + 2O2 -> CO2 + 2H2O}\]

  • \[\ce{CH4 + 4Cl2 -> CCl4 + 4HCl}\]

  • \[\ce{2F2 + 2OH- -> 2F- + OF2 + H2O}\]

  • \[\ce{2NO2 + 2OH- -> NO^{-}2 + NO^{-}3 + H2O}\]

MCQ
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Solution

\[\ce{2NO2 + 2OH- -> NO^{-}2 + NO^{-}3 + H2O}\]

Explanation:

Disproportionate reactions are defined as the reactions in which the same substance is oxidized as well as reduced. Here, the below reaction is given as-

\[\ce{2NO2 + 2OH- -> NO^{-}2 + NO^{-}3 + H2O}\]

In this reaction, N is both oxidized as well as reduced since O.N. of N increases from +4 in \[\ce{NO^{-}3}\] to +5 in \[\ce{NO2}\] and decreases from +4 in \[\ce{NO}\] to +3 in \[\ce{NO^{-}2}\].

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Oxidation Number - Types of Redox Reactions
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Chapter 8: Redox Reactions - Multiple Choice Questions (Type - I) [Page 106]

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NCERT Exemplar Chemistry [English] Class 11
Chapter 8 Redox Reactions
Multiple Choice Questions (Type - I) | Q 10 | Page 106

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