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Question
Find n, if `"n"/(6!) = 4/(8!) + 3/(6!)`
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Solution
`"n"/(6!) = 4/(8!) + 3/(6!)`
∴ `"n"/(6!) - 3/(6!) = 4/(8!)`
∴ `("n" - 3)/(6!) = 4/(8 xx 7 xx 6!)`
∴ n – 3 = `4/(8 xx 7)`
∴ n – 3 = `1/(2 xx 7)`
∴ n – 3 = `1/14`
∴ n = `1/14 + 3`
∴ n = `(1 + 42)/14 `
= `43/14`
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