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Question
Simplify `(("n" + 3)!)/(("n"^2 - 4)("n" + 1)!)`
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Solution
`(("n" + 3)!)/(("n"^2 - 4)("n" + 1)!) = (("n" + 3)("n" + 2)("n" + 1)!)/(("n"^2 - 4)("n" + 1)!)`
= `(("n" + 3)("n" + 2))/("n"^2 - 4)`
= `(("n" + 3)("n" + 2))/(("n" - 2)("n" + 2))`
= `("n" + 3)/("n" - 2)`.
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