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Find n, if (n + 3)! = 110 × (n + 1)!

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Question

Find n, if (n + 3)! = 110 × (n + 1)!

Sum
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Solution

(n + 3)! = 110 × (n + 1)!

(n + 3)(n + 2)(n + 1)! = 110(n + 1)!

∴ (n + 3)(n + 2) = 110

∴ n2 + 5n + 6 = 110

∴ n2 + 5n + 6 – 110 = 0

∴ n2 + 5n – 104 = 0

∴ n2 + 13n – 8n – 104 = 0

∴ n(n + 13) – 8(n + 13) = 0

∴ (n + 13)(n – 8) = 0

∴ n + 13 = 0 or n – 8 = 0

∴ n = – 13 or n = 8

But n ∈ N

∴ n ≠ – 13

Hence, n = 8.

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Chapter 3: Permutations and Combination - Exercise 3.2 [Page 49]

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Balbharati Mathematics and Statistics 2 (Arts and Science) [English] Standard 11 Maharashtra State Board
Chapter 3 Permutations and Combination
Exercise 3.2 | Q 5. (v) | Page 49

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