English

Compute: 12!6! - Mathematics and Statistics

Advertisements
Advertisements

Question

Compute: `(12!)/(6!)`

Sum
Advertisements

Solution

`(12!)/(6!) = (12 xx 11 xx 10 xx 9 xx 8 xx 7 xx 6!)/(6!)`

= 12 × 11 × 10 × 9 × 8 × 7

= 665280

shaalaa.com
Factorial Notation
  Is there an error in this question or solution?
Chapter 3: Permutations and Combination - Exercise 3.2 [Page 49]

APPEARS IN

Balbharati Mathematics and Statistics 2 (Arts and Science) [English] Standard 11 Maharashtra State Board
Chapter 3 Permutations and Combination
Exercise 3.2 | Q 2. (i) | Page 49

RELATED QUESTIONS

Evaluate: 8!


Evaluate: 10!


Compute: (3 × 2)!


Compute: `(6! - 4!)/(4!)`


Compute: `(8!)/(6! - 4!)`


Compute: `(8!)/((6 - 4)!)`


Write in terms of factorial.

3 × 6 × 9 × 12 × 15


Evaluate : `("n"!)/("r"!("n" - "r")!)` for n = 8, r = 6


Evaluate : `("n"!)/("r"!("n" - "r")!)` for n = 12, r = 12


Find n, if `(1!)/("n"!) = (1!)/(4!) - 4/(5!)`


Find n, if (n + 1)! = 42 × (n – 1)!


Find n, if (n + 3)! = 110 × (n + 1)!


Find n, if: `((17 - "n")!)/((14 - "n")!)` = 5!


Find n, if: `("n"!)/(3!("n" - 3)!) : ("n"!)/(5!("n" - 5)!)` = 5 : 3


Find n, if: `("n"!)/(3!("n" - 3)!) : ("n"!)/(5!("n" - 7)!)` = 1 : 6


Find n, if: `((2"n")!)/(7!(2"n" - 7)!) : ("n"!)/(4!("n" - 4)!)` = 24 : 1


Show that `(9!)/(3!6!) + (9!)/(4!5!) = (10!)/(4!6!)`


Simplify `((2"n" + 2)!)/((2"n")!)`


Simplify `(("n" + 3)!)/(("n"^2 - 4)("n" + 1)!)`


Simplify `1/("n"!) - 1/(("n" - 1)!) - 1/(("n" - 2)!)`


Simplify n[n! + (n – 1)!] + n2(n – 1)! + (n + 1)!


Simplify `("n" + 2)/("n"!) - (3"n" + 1)/(("n" + 1)!)`


Simplify `1/("n"!) - 3/(("n" + 1)!) - ("n"^2 - 4)/(("n" + 2)!)`


Simplify `("n"^2 - 9)/(("n" + 3)!) + 6/(("n" + 2)!) - 1/(("n" + 1)!)`


Select the correct answer from the given alternatives.

In how many ways 4 boys and 3 girls can be seated in a row so that they are alternate


Select the correct answer from the given alternatives.

Find the number of triangles which can be formed by joining the angular points of a polygon of 8 sides as vertices.


Find the number of integers greater than 7,000 that can be formed using the digits 4, 6, 7, 8, and 9, without repetition: ______


If `((11 - "n")!)/((10 - "n")!) = 9,`then n = ______.


Let Tn denote the number of triangles which can be formed using the vertices of a regular polygon of n sides. If Tn + 1 – Tn = 21, then n is equal to ______.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×