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Question
Find the interval in which the following function are increasing or decreasing f(x) = x3 − 12x2 + 36x + 17 ?
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Solution
\[\text { When } \left( x - a \right)\left( x - b \right)>0 \text { with }a < b, x < a \text { or }x>b.\]
\[\text { When } \left( x - a \right)\left( x - b \right)<0 \text { with } a < b, a < x < b .\]
\[f\left( x \right) = x^3 - 12 x^2 + 36x + 17\]
\[f'\left( x \right) = 3 x^2 - 24x + 36\]
\[ = 3 \left( x^2 - 8x + 12 \right)\]
\[ = 3 \left( x - 2 \right)\left( x - 6 \right)\]
\[\text { For }f(x) \text { to be increasing, we must have }\]
\[f'\left( x \right) > 0\]
\[ \Rightarrow 3 \left( x - 2 \right)\left( x - 6 \right) > 0\]
\[ \Rightarrow \left( x - 2 \right)\left( x - 6 \right) > 0 \left[ \text { Since } 3 > 0, 3 \left( x - 2 \right)\left( x - 6 \right) > 0 \Rightarrow \left( x - 2 \right)\left( x - 6 \right) > 0 \right]\]
⇒ x < 2 or x > 6
\[ \Rightarrow x \in \left( - \infty , 2 \right) \cup \left( 6, \infty \right)\]
\[\text { So },f(x)\text { is increasing on } x \in \left( - \infty , 2 \right) \cup \left( 6, \infty \right).\]
\[\text { For }f(x) \text { to be decreasing, we must have }\]
\[f'\left( x \right) < 0\]
\[ \Rightarrow 3 \left( x - 2 \right)\left( x - 6 \right) < 0\]
\[ \Rightarrow \left( x - 2 \right)\left( x - 6 \right) < 0 \left[ \text { Since } 3 > 0, 3 \left( x - 2 \right)\left( x - 6 \right) < 0 \Rightarrow \left( x - 2 \right)\left( x - 6 \right) < 0 \right]\]
\[ \Rightarrow 2 < x < 6 \]
\[ \Rightarrow x \in \left( 2, 6 \right)\]
\[\text { So,}f(x)\text { is decreasing on } x \in \left( 2, 6 \right) .\]
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