English
Maharashtra State BoardSSC (English Medium) 10th Standard

Find the 27th Term of the Following A.P. 9, 4, –1, –6, –11,...

Advertisements
Advertisements

Question

Find the 27th term of the following A.P.
9, 4, –1, –6, –11,...

Sum
Advertisements

Solution

The given sequence is 9, 4, –1, –6, –11,...
Here,
First term (a) = 9 
Common difference (d) = a2 – a1 = 4 – (9) = –5
Now,

\[a_{27} = a + \left( n - 1 \right)d\]
\[ = 9 + \left( 27 - 1 \right)\left( - 5 \right)\]
\[ = 9 + \left( 26 \right)\left( - 5 \right)\]
\[ = - 121\]

Hence, the 27th term of the progression is –121.

shaalaa.com
  Is there an error in this question or solution?
Chapter 3: Arithmetic Progression - Practice Set 3.2 [Page 66]

APPEARS IN

Balbharati Algebra Mathematics 1 [English] Standard 10 Maharashtra State Board
Chapter 3 Arithmetic Progression
Practice Set 3.2 | Q 5 | Page 66

RELATED QUESTIONS

Find the term t15 of an A.P. : 4, 9, 14, …………..


Find the sum of the following arithmetic series:

34 + 32 + 30 + ... + 10


Given Arithmetic Progression 12, 16, 20, 24, . . . Find the 24th term of this progression.


Six year before, the age of mother was equal to the square of her son's age. Three year hence, her age will be thrice the age of her son then. Find the present ages of the mother and son.


Select the correct alternative and write it. 

What is the sum of first n natural numbers ? 

 


If the sum of first n terms of an AP is n2, then find its 10th term.


If third term and fifth term of an A.P. are 13 and 25 respectively, find its 7th term.


Find tn if a = 20 and d = 3.


Find t5 if a = 3 and d = –3.


How many two-digit numbers are divisible by 5?

Activity :-  Two-digit numbers divisible by 5 are, 10, 15, 20, ......, 95.

Here, d = 5, therefore this sequence is an A.P.

Here, a = 10, d = 5, tn = 95, n = ?

tn = a + (n – 1) `square`

`square` = 10 + (n – 1) × 5

`square` = (n – 1) × 5

`square` = (n – 1)

Therefore n = `square`

There are `square` two-digit numbers divisible by 5.


Decide whether 301 is term of given sequence 5, 11, 17, 23,.....

Activity :-  Here, d = `square`, therefore this sequence is an A.P.

a = 5, d = `square`

Let nth term of this A.P. be 301.

tn = a + (n – 1) `square`

301 = 5 + (n – 1) × `square`

301 = 6n – 1

n = `302/6` = `square`

But n is not positive integer.

Therefore, 301 is `square` the term of sequence 5, 11, 17, 23,......


12, 16, 20, 24,...... Find 25th term of this A.P.


If p - 1, p + 3, 3p - 1 are in AP, then p is equal to ______.


In an A.P. if the sum of third and seventh term is zero. Find its 5th term.


Write the next two terms of the A.P.: `sqrt(27), sqrt(48), sqrt(75)`......


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×