Advertisements
Advertisements
प्रश्न
Find the 27th term of the following A.P.
9, 4, –1, –6, –11,...
Advertisements
उत्तर
The given sequence is 9, 4, –1, –6, –11,...
Here,
First term (a) = 9
Common difference (d) = a2 – a1 = 4 – (9) = –5
Now,
\[a_{27} = a + \left( n - 1 \right)d\]
\[ = 9 + \left( 27 - 1 \right)\left( - 5 \right)\]
\[ = 9 + \left( 26 \right)\left( - 5 \right)\]
\[ = - 121\]
Hence, the 27th term of the progression is –121.
APPEARS IN
संबंधित प्रश्न
If the 9th term of an A.P. is zero, then prove that 29th term is double of 19th term.
Find the sum of the following arithmetic series:
`7 + 10 1/2 + 14 + ....... + 84`
Find the 19th term of the following A.P.:
7, 13, 19, 25, ...
Select the correct alternative and write it.
What is the sum of first n natural numbers ?
Select the correct alternative and write it.
If a share is at premium, then -
For a given A.P. a = 3.5, d = 0, then tn = _______.
If the sum of first n terms of an AP is n2, then find its 10th term.
How many multiples of 4 lie between 10 and 205?
If third term and fifth term of an A.P. are 13 and 25 respectively, find its 7th term.
Find tn if a = 20 and d = 3.
Find t5 if a = 3 and d = –3.
Decide whether 301 is term of given sequence 5, 11, 17, 23,.....
Activity :- Here, d = `square`, therefore this sequence is an A.P.
a = 5, d = `square`
Let nth term of this A.P. be 301.
tn = a + (n – 1) `square`
301 = 5 + (n – 1) × `square`
301 = 6n – 1
n = `302/6` = `square`
But n is not positive integer.
Therefore, 301 is `square` the term of sequence 5, 11, 17, 23,......
12, 16, 20, 24,...... Find 25th term of this A.P.
If tn = 2n – 5 is the nth term of an A.P., then find its first five terms.
The nth term of an A.P. 5, 8, 11, 14,...... is 68. Find n = ?
If p - 1, p + 3, 3p - 1 are in AP, then p is equal to ______.
In an A.P. if the sum of third and seventh term is zero. Find its 5th term.
Write the next two terms of the A.P.: `sqrt(27), sqrt(48), sqrt(75)`......
