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प्रश्न
Find the 27th term of the following A.P.
9, 4, –1, –6, –11,...
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उत्तर
The given sequence is 9, 4, –1, –6, –11,...
Here,
First term (a) = 9
Common difference (d) = a2 – a1 = 4 – (9) = –5
Now,
\[a_{27} = a + \left( n - 1 \right)d\]
\[ = 9 + \left( 27 - 1 \right)\left( - 5 \right)\]
\[ = 9 + \left( 26 \right)\left( - 5 \right)\]
\[ = - 121\]
Hence, the 27th term of the progression is –121.
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