Question

Find the 19^th term of the following A.P.:

7, 13, 19, 25, ...

Answer 1

The given sequence is 7, 13, 19, 25, ....

Here,

First term = a = t₁ = 7, t₂ = 13, t₃ = 19, t₄ = 25, ....

Common difference = d = t₂ − t₁

= 13 – 7

= 6

To find the 19^th term, we have to use the formula, i.e.,

t_n = a + (n − 1)d

∴ t₁₉ = 7 + (19 − 1) × 6 ...(On substituting value)

= 7 + 18 × 6

= 7 + 108

= 115

Hence, the 19^th term of the progression is 115.