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महाराष्ट्र राज्य शिक्षण मंडळएस.एस.सी (इंग्रजी माध्यम) इयत्ता १० वी

Find the 19th term of the following A.P.: 7, 13, 19, 25, ...

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प्रश्न

Find the 19th term of the following A.P.:

7, 13, 19, 25, ...

बेरीज
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उत्तर

The given sequence is 7, 13, 19, 25, ....

Here,

First term = a = t1 = 7, t2 = 13, t3 = 19, t4 = 25, ....

Common difference = d = t2 − t1

= 13 – 7

= 6

To find the 19th term, we have to use the formula, i.e.,

tn = a + (n − 1)d

∴ t19 = 7 + (19 − 1) × 6 ...(On substituting value)

= 7 + 18 × 6

= 7 + 108

= 115

Hence, the 19th term of the progression is 115.

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पाठ 3: Arithmetic Progression - Practice Set 3.2 [पृष्ठ ६६]

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बालभारती Algebra Mathematics 1 [English] Standard 10 Maharashtra State Board
पाठ 3 Arithmetic Progression
Practice Set 3.2 | Q 4 | पृष्ठ ६६
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