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महाराष्ट्र राज्य शिक्षण मंडळएस.एस.सी (इंग्रजी माध्यम) इयत्ता १० वी

Choose the correct alternative answer for the following sub-question If the third term and fifth term of an A.P. are 13 and 25 respectively, find its 7th term - Algebra

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प्रश्न

Choose the correct alternative answer for the following sub-question

If the third term and fifth term of an A.P. are 13 and 25 respectively, find its 7th term

पर्याय

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MCQ
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उत्तर

37

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पाठ 3: Arithmetic Progression - Q.1 (A)

संबंधित प्रश्‍न

If the 9th term of an A.P. is zero, then prove that 29th term is double of 19th term.


Find the sum of  the following arithmetic series:

34 + 32 + 30 +...+10


Find the sum of the following arithmetic series:

(-5)+(-8)+(-11)+...+(-230)


Find the 19th term of the following A.P.:

7, 13, 19, 25, ...


Find the 27th term of the following A.P.
9, 4, –1, –6, –11,...


Select the correct alternative and write it. 

What is the sum of first n natural numbers ? 

 


Select the correct alternative and write it. 

If a share is at premium, then - 


For a given A.P. a = 3.5, d = 0, then tn = _______.


Find the 23rd term of the following A.P.: 9, 4,-1,-6,-11.


If the sum of first n terms of an AP is n2, then find its 10th term. 


How many multiples of 4 lie between 10 and 205?


Find t5 if a = 3 आणि d = −3


Decide whether the given sequence 24, 17, 10, 3, ...... is an A.P.? If yes find its common term (tn)


How many two-digit numbers are divisible by 5?

Activity :-  Two-digit numbers divisible by 5 are, 10, 15, 20, ......, 95.

Here, d = 5, therefore this sequence is an A.P.

Here, a = 10, d = 5, tn = 95, n = ?

tn = a + (n − 1) `square`

`square` = 10 + (n – 1) × 5

`square` = (n – 1) × 5

`square` = (n – 1)

Therefore n = `square`

There are `square` two-digit numbers divisible by 5


12, 16, 20, 24, ...... Find 25th term of this A.P.


If tn = 2n – 5 is the nth term of an A.P., then find its first five terms


Find a and b so that the numbers a, 7, b, 23 are in A.P.


In an A.P. if the sum of third and seventh term is zero. Find its 5th term.


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