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महाराष्ट्र राज्य शिक्षण मंडळएस.एस.सी (इंग्रजी माध्यम) इयत्ता १० वी

Given Arithmetic Progression 12, 16, 20, 24, . . . Find the 24th term of this progression.

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प्रश्न

Given Arithmetic Progression 12, 16, 20, 24, . . . Find the 24th term of this progression.

Given A.P. is 12, 16, 20, 24, ...... Find the 24th term of this progression.

बेरीज
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उत्तर

The given sequence is 12, 16, 20, 24,...

Here,

First term (a) = 12

Common difference (d) = a2 – a1

= 16 – (12)

= 4
Now,

a24 = a + (n – 1)d

∴ a24 = 12 + (24 – 1) 4

= 12 + 23 × 4

= 12 + 92

= 104

Hence, the 24th term of the progression is 104. 

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पाठ 3: Arithmetic Progression - Practice Set 3.2 [पृष्ठ ६६]

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बालभारती Algebra Mathematics 1 [English] Standard 10 Maharashtra State Board
पाठ 3 Arithmetic Progression
Practice Set 3.2 | Q 3 | पृष्ठ ६६

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