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Maharashtra State BoardSSC (English Medium) 10th Standard

Given Arithmetic Progression 12, 16, 20, 24, . . . Find the 24th term of this progression. - Algebra Mathematics 1

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Questions

Given Arithmetic Progression 12, 16, 20, 24, . . . Find the 24th term of this progression.

Given A.P. is 12, 16, 20, 24, ...... Find the 24th term of this progression.

Sum
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Solution

The given sequence is 12, 16, 20, 24,...

Here,

First term (a) = 12

Common difference (d) = a2 – a1

= 16 – (12)

= 4
Now,

a24 = a + (n – 1)d

∴ a24 = 12 + (24 – 1) 4

= 12 + 23 × 4

= 12 + 92

= 104

Hence, the 24th term of the progression is 104. 

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Chapter 3: Arithmetic Progression - Practice Set 3.2 [Page 66]

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Balbharati Algebra (Mathematics 1) [English] Standard 10 Maharashtra State Board
Chapter 3 Arithmetic Progression
Practice Set 3.2 | Q 3 | Page 66
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