Advertisements
Advertisements
प्रश्न
Write the next two terms of the A.P.: `sqrt(27), sqrt(48), sqrt(75)`......
Advertisements
उत्तर
Given A.P. is `sqrt(27), sqrt(48), sqrt(75)` ......
Here, a1 = `sqrt(27) = 3sqrt(3)`
a2 = `sqrt(48) = 4sqrt(3)`
∴ Common difference = `4sqrt(3) - 3sqrt(3)`
= `sqrt(3) (4 - 3) = sqrt(3)`
Now, Given a3 = `sqrt(75) = 5sqrt(3)`
∴ a4 = `6sqrt(3) = sqrt(108)`
And a5 = `7sqrt(3) = sqrt(147)`
Hence, next two terms are `sqrt(108)` and `sqrt(147)`.
संबंधित प्रश्न
Find the term t15 of an A.P. : 4, 9, 14, …………..
Find the sum of the following arithmetic series:
`7 + 10 1/2 + 14 + ....... + 84`
Decide whether the following sequence is an A.P., if so find the 20th term of the progression:
–12, –5, 2, 9, 16, 23, 30, ..............
Given Arithmetic Progression 12, 16, 20, 24, . . . Find the 24th term of this progression.
Select the correct alternative and write it.
What is the sum of first n natural numbers ?
For a given A.P. a = 3.5, d = 0, then tn = _______.
Find tn if a = 20 and d = 3.
Decide whether the given sequence 24, 17, 10, 3,...... is an A.P.? If yes find its common term (tn).
How many two-digit numbers are divisible by 5?
Activity :- Two-digit numbers divisible by 5 are, 10, 15, 20, ......, 95.
Here, d = 5, therefore this sequence is an A.P.
Here, a = 10, d = 5, tn = 95, n = ?
tn = a + (n – 1) `square`
`square` = 10 + (n – 1) × 5
`square` = (n – 1) × 5
`square` = (n – 1)
Therefore n = `square`
There are `square` two-digit numbers divisible by 5.
If tn = 2n – 5 is the nth term of an A.P., then find its first five terms.
