Question

Determine the 36^th term of the A.P. whose first two terms are –3 and 4 respectively.

Answer 1

Given, first two terms of AP are –3 and 4.

∴ a₁ = –3 and a₂ = 4

∴ Common difference, d = 4 – (–3) = 4 + 3 = 7

We know that, n^th term of A.P. is T_n = a + (n – 1)d

∴ T₃₆ = a + (36 – 1)d

= –3 + 35(7)

= –3 + 245

= 242