Advertisements
Advertisements
प्रश्न
Find t5 if a = 3 and d = –3.
Advertisements
उत्तर
tn = a + (n – 1)d
∴ t5 = 3 + (5 – 1)(– 3)
= 3 + 4(– 3)
= 3 – 12
= – 9
संबंधित प्रश्न
Find the term t15 of an A.P. : 4, 9, 14, …………..
Decide whether the following sequence is an A.P., if so find the 20th term of the progression:
–12, –5, 2, 9, 16, 23, 30, ..............
Find the 19th term of the following A.P.:
7, 13, 19, 25, ...
Find the 27th term of the following A.P.
9, 4, –1, –6, –11,...
For a given A.P. a = 3.5, d = 0, then tn = _______.
Find the 23rd term of the following A.P.: 9, 4,-1,-6,-11.
How many multiples of 4 lie between 10 and 205?
Find tn if a = 20 and d = 3.
Decide whether the given sequence 24, 17, 10, 3,...... is an A.P.? If yes find its common term (tn).
How many two-digit numbers are divisible by 5?
Activity :- Two-digit numbers divisible by 5 are, 10, 15, 20, ......, 95.
Here, d = 5, therefore this sequence is an A.P.
Here, a = 10, d = 5, tn = 95, n = ?
tn = a + (n – 1) `square`
`square` = 10 + (n – 1) × 5
`square` = (n – 1) × 5
`square` = (n – 1)
Therefore n = `square`
There are `square` two-digit numbers divisible by 5.
Decide whether 301 is term of given sequence 5, 11, 17, 23,.....
Activity :- Here, d = `square`, therefore this sequence is an A.P.
a = 5, d = `square`
Let nth term of this A.P. be 301.
tn = a + (n – 1) `square`
301 = 5 + (n – 1) × `square`
301 = 6n – 1
n = `302/6` = `square`
But n is not positive integer.
Therefore, 301 is `square` the term of sequence 5, 11, 17, 23,......
If tn = 2n – 5 is the nth term of an A.P., then find its first five terms.
The nth term of an A.P. 5, 8, 11, 14,...... is 68. Find n = ?
If p - 1, p + 3, 3p - 1 are in AP, then p is equal to ______.
Write the next two terms of the A.P.: `sqrt(27), sqrt(48), sqrt(75)`......
