Advertisements
Advertisements
Question
Factorize the following expressions:
x3y3 + 1
Advertisements
Solution
= ( xy)3 +13
= ( xy +1)(( xy)2 - xy x 1+12 ) [∵ a3 + b3 = (a + b)(a2 - ab + b2 )]
= ( xy +1)(x2 y2 - xy +1)
∴ x3 y3 +1 = ( xy +1)(x2 y2 - xy +1)
shaalaa.com
Is there an error in this question or solution?
APPEARS IN
RELATED QUESTIONS
Factorize `21x^2 - 2x + 1/21`
Factorize `8/27 x^3 + 1 + 4/3 x^2 + 2x`
Factorize 8a3 + 27b3 + 36a2b + 54ab2
a3 + 8b3 + 64c3 - 24abc
If a2 + b2 + c2 = 250 and ab + bc + ca = 3, find a + b + c.
If 3x = a + b + c, then the value of (x − a)3 + (x −b)3 + (x − c)3 − 3(x − a) (x − b) (x −c) is
Evaluate: (6p2 - 8pq + 2q2) (- 5p)
Multiply: (6x - 2y)(3x - y)
Divide: 25x2y by - 5y2
Express the following properties with variables x, y and z.
Distributive property of multiplication over addition
