Advertisements
Advertisements
प्रश्न
Factorize the following expressions:
x3y3 + 1
Advertisements
उत्तर
= ( xy)3 +13
= ( xy +1)(( xy)2 - xy x 1+12 ) [∵ a3 + b3 = (a + b)(a2 - ab + b2 )]
= ( xy +1)(x2 y2 - xy +1)
∴ x3 y3 +1 = ( xy +1)(x2 y2 - xy +1)
shaalaa.com
या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
APPEARS IN
संबंधित प्रश्न
Factorize: a2 + b2 + 2 (ab + bc + ca)
Factorize `x^2 + 6sqrt2x + 10`
Factorize the following expressions:
`a^3 - 1/a^3 - 2a + 2/a`
(2x - 3y)3 + (4z - 2x)3 + (3y - 4z )3
The factors of x4 + x2 + 25 are
Evaluate: (a2 + b2 + c2 - ab - bc - ca)(a + b + c)
Divide: 25x2y by - 5y2
Divide: 6x2 - xy - 35y2 by 2x - 5y
Complete the table.
| × | 2x2 | −2xy | x4y3 | 2xyz | (___)xz2 |
| x4 | |||||
| (___) | 4x5y4 | ||||
| −x2y | |||||
| 2y2z | −10xy2z3 | ||||
| −3xyz | |||||
| (___) | −14xyz2 |
In the term 10xyz, what is the numerical coefficient?
