Advertisements
Advertisements
Question
Factorize the following expressions:
1029 – 3x3
Advertisements
Solution
= 3(343 - x3)
= 3(73 - x3)
= 3(7 - x)(72 + 7 x x + x2) [∵ a3 - b3 = (a - b)(a2 + ab + b2) ]
= 3(7 - x)(49 + 7x + x2 )
∴ 1029 - 3x3 = 3(7 - x)(49 + 7x + x2 )
APPEARS IN
RELATED QUESTIONS
Factorize x3 - 2x2 y + 3xy2 - 6y3
Factorize `x^2 + 12/35 x + 1/35`
Factorize `21x^2 - 2x + 1/21`
Factorize the following expressions:
`a^3 - 1/a^3 - 2a + 2/a`
Multiply: x2 + 4y2 + 2xy − 3x + 6y + 9 by x − 2y + 3
If a2 + b2 + c2 = 250 and ab + bc + ca = 3, find a + b + c.
The factors of x3 − 1 + y3 + 3xy are
Separate monomials, binomials, trinomials and polynomials from the following algebraic expressions :
8 − 3x, xy2, 3y2 − 5y + 8, 9x − 3x2 + 15x3 − 7,
3x × 5y, 3x ÷ 5y, 2y ÷ 7 + 3x − 7 and 4 − ax2 + bx + y
Multiply: (2x + 5y + 6)(3x + y - 8)
Divide: m2 − 2mn + n2 by m − n
