Advertisements
Advertisements
Question
Factorize the following:
2a4b4 − 3a3b5 + 4a2b5
Advertisements
Solution
The greatest common factor of the terms 2a4b4, -3a3b5 and 4a2b5 of the expression 2a4b4 - 3a3b5 + 4a2b5 is a2b4.
Now,
2a4b4 = a2b4 X 2a2
-3a3b5 = a2b4 X -3ab
4a2b5 = a2b4 X 4b
Hence, (2a4b4 - 3a3b5 + 4a2b5) can be factorised as [a2b4(2a2 - 3ab + 4b)].
APPEARS IN
RELATED QUESTIONS
Factorise the following expression:
5x2y − 15xy2
Factorize the following:
72x6y7 − 96x7y6
Factorise:
`x^2 + 1/(4x^2) + 1 - 7x - 7/(2x)`
Factorise:
`x^4 + y^4 - 27x^2y^2`
Factorise : 12(3x - 2y)2 - 3x + 2y - 1
Factorise : `1/4 ( a + b )^2 - 9/16 ( 2a - b )^2`
Factorise : 4a2 - 8ab
factorise : ab(x2 + y2) - xy (a2 + b2)
Factorise the following by taking out the common factors:
(mx + ny)2 + (nx - my)2
Factorise the following by taking out the common factors:
36(x + y)3 - 54(x + y)2
