Advertisements
Advertisements
प्रश्न
Factorize the following:
2a4b4 − 3a3b5 + 4a2b5
Advertisements
उत्तर
The greatest common factor of the terms 2a4b4, -3a3b5 and 4a2b5 of the expression 2a4b4 - 3a3b5 + 4a2b5 is a2b4.
Now,
2a4b4 = a2b4 X 2a2
-3a3b5 = a2b4 X -3ab
4a2b5 = a2b4 X 4b
Hence, (2a4b4 - 3a3b5 + 4a2b5) can be factorised as [a2b4(2a2 - 3ab + 4b)].
APPEARS IN
संबंधित प्रश्न
Factorise the following expression:
7a2 + 14a
Factorise the following expression:
x2yz + xy2z + xyz2
Factorize the following:
9x2y + 3axy
Factorize the following:
16m − 4m2
Factorise:
(2a - 3)2 - 2 (2a - 3) (a - 1) + (a - 1)2
Factorise : 6x2y + 9xy2 + 4y3
Factorise : (a+ 2b) (3a + b) - (a+ b) (a+ 2b) +(a+ 2b)2
Factorise xy2 - xz2, Hence, find the value of :
9 x 82 - 9 x 22
Factorise:
`4"a"^2 + (1)/(4"a"^2) - 2 - 6"a" + (3)/(2"a")`
Factorise the following by taking out the common factor
18xy – 12yz
