Advertisements
Advertisements
Question
factorise: b(c - d)2 + a(d - c) + 3(c - d)
Sum
Advertisements
Solution
b(c - d)2 + a(d - c) + 3(c - d)
= b (c - d)2 - a(c - d) + 3(c - d)
= (c - d) [b (c - d) - a + 3]
= (c - d) (bc - bd - a + 3)
shaalaa.com
Factorisation by Grouping
Is there an error in this question or solution?
APPEARS IN
RELATED QUESTIONS
Factorise by the grouping method : y2 - (a + b) y + ab
Factorise : a2 - ab - ca + bc
factorise: a2 + 5a + 6
factorise: a2 - 23a + 42
factorise: 3a2x - bx + 3a2 - b
factorise: ax2 + b2y - ab2 - x2y
Factorise the following by grouping the terms:
15x2 + 7y - 3x - 35xy
Factorise the following by grouping the terms:
x(x - 4)- x + 4
Factorise the following by grouping the terms:
4abx2 + 49aby2 + 14xy(a2 + b2)
Factorise the following by grouping the terms:
3ax2 - 5bx2 + 9az2 + 6ay2 - 10by2 - 15bz2
