Advertisements
Advertisements
Question
factorise: b(c - d)2 + a(d - c) + 3(c - d)
Sum
Advertisements
Solution
b(c - d)2 + a(d - c) + 3(c - d)
= b (c - d)2 - a(c - d) + 3(c - d)
= (c - d) [b (c - d) - a + 3]
= (c - d) (bc - bd - a + 3)
shaalaa.com
Factorisation by Grouping
Is there an error in this question or solution?
APPEARS IN
RELATED QUESTIONS
Factorise using the grouping method :
m (x - 3y)2 + n (3y - x) + 5x - 15y
Factorise : a2 - ab - ca + bc
Factorise : x2 - (b - 2)x - 2b
Factorise : 2ab2 - aby + 2cby - cy2
Factorise: 7b2 - 8b + 1
factorise: 14x2 + x - 3
factorise: 5 + 3a - 14a2
Factorise the following by grouping the terms:
x(x - 4)- x + 4
Factorise the following by grouping the terms:
2a + b + 3c - d + (2a + b)3 + (2a + b)2(3c - d)
Factorise the following by grouping the terms:
x2 - (p + q)x + pq
