Factorise : 6a2 - 3a2b - Bc2 + 2c2 - Mathematics

Factorise : 6a² - 3a²b - bc² + 2c²

Sum

6a² - 3a²b - bc² + 2c²

= 6a² - 3a²b + 2c² - bc²

= 3a² (2 - b) + c² (2 - b)

= (2 - b) (3a² + c²)

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Factorisation by Grouping

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Chapter 13: Factorisation - Exercise 13 (B) [Page 158]

Chapter 13 Factorisation
Exercise 13 (B) | Q 9 | Page 158

Factorise by the grouping method : ab - 2b + a² - 2a

Factorise by the grouping method :
`a^2 + 1/a^2 - 2 - 3a + 3/a`

Factorise : ab(c² + d²) - a²cd - b²cd

Factorise : ax + 2bx + 3cx - 3a - 6b - 9c

factorise: x² - 10xy + 24y²

factorise: a² - 23a + 42

factorise: 3a²x - bx + 3a² - b

Factorise the following by grouping the terms:
x(x - 4)- x + 4

Factorise the following by grouping the terms:
p²x² + (px² + 1)x + p

Factorise the following by grouping the terms:
x + y + m(x + y)