Factorise : 6a2 - 3a2b - Bc2 + 2c2 - Mathematics

Factorise : 6a² - 3a²b - bc² + 2c²

Sum

6a² - 3a²b - bc² + 2c²

= 6a² - 3a²b + 2c² - bc²

= 3a² (2 - b) + c² (2 - b)

= (2 - b) (3a² + c²)

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Factorisation by Grouping

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Chapter 13: Factorisation - Exercise 13 (B) [Page 158]

Chapter 13 Factorisation
Exercise 13 (B) | Q 9 | Page 158

Factorise by the grouping method : a⁴ - 2a³ - 4a + 8

Factorise by the grouping method : a²x² + (ax² + 1) x + a

Factorise using the grouping method :
a² + 4b² - 3a + 6b - 4ab

Factorise : xy - ay - ax + a² + bx - ab

Factorise : a³ - a² - ab + a + b - 1

Factorise : 2ab²c - 2a + 3b³c - 3b - 4b²c² + 4c

factorise: 5 + 7x - 6x²

factorise: 8 + 6(a + b) - 5(a + b)²

factorise: 3a²x - bx + 3a² - b

Factorise the following by grouping the terms:
x + y + m(x + y)