Factorise : 6a2 - 3a2b - Bc2 + 2c2

Factorise : 6a² - 3a²b - bc² + 2c²

Sum

6a² - 3a²b - bc² + 2c²

= 6a² - 3a²b + 2c² - bc²

= 3a² (2 - b) + c² (2 - b)

= (2 - b) (3a² + c²)

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Factorisation by Grouping

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Chapter 13: Factorisation - Exercise 13 (B) [Page 158]

Chapter 13 Factorisation
Exercise 13 (B) | Q 9 | Page 158

Factorise by the grouping method : a³ + a - 3a² - 3

Factorise using the grouping method :
m (x - 3y)² + n (3y - x) + 5x - 15y

Factorise : a(b − c) − d(c − b)

Factorise : ab² - (a - c) b - c

factorise: 2a² + 7a + 6

Factorise: 7b² - 8b + 1

factorise: ax² + b²y - ab² - x²y

Factorise the following by grouping the terms:
p²x² + (px² + 1)x + p

Factorise the following by grouping the terms:
x² - (p + q)x + pq

Factorise the following by grouping the terms:
x + y + m(x + y)