Factorise : 6a2 - 3a2b - Bc2 + 2c2

Factorise : 6a² - 3a²b - bc² + 2c²

बेरीज

6a² - 3a²b - bc² + 2c²

= 6a² - 3a²b + 2c² - bc²

= 3a² (2 - b) + c² (2 - b)

= (2 - b) (3a² + c²)

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Factorisation by Grouping

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पाठ 13: Factorisation - Exercise 13 (B) [पृष्ठ १५८]

पाठ 13 Factorisation
Exercise 13 (B) | Q 9 | पृष्ठ १५८

Factorize using the grouping method:

x² + y² + x + y + 2xy

Factorise : ab - 2b + a² - 2a

Factorise : 3x⁵ - 6x⁴ - 2x³ + 4x² + x - 2

Factorise : 2ab²c - 2a + 3b³c - 3b - 4b²c² + 4c

Factorise the following by grouping the terms:
15xy - 9x - 25y + 15

Factorise the following by grouping the terms:
2m³ - 5n² - 5m²n + 2mn

Factorise the following by grouping the terms:
3ax² - 5bx² + 9az² + 6ay² - 10by² - 15bz²

Factorise the following by grouping the terms:
xy(a² + 1) + a(x² + y²)

Factorise the following by grouping the terms:
x² - (p + q)x + pq

Factorise the following by grouping the terms:

`(1)/(25x^2) + 16x^2 + (8)/(5) - 12x - (3)/(5x)`