Advertisements
Advertisements
प्रश्न
Factorise : 6a2 - 3a2b - bc2 + 2c2
योग
Advertisements
उत्तर
6a2 - 3a2b - bc2 + 2c2
= 6a2 - 3a2b + 2c2 - bc2
= 3a2 (2 - b) + c2 (2 - b)
= (2 - b) (3a2 + c2)
shaalaa.com
Factorisation by Grouping
क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
APPEARS IN
संबंधित प्रश्न
Factorise by the grouping method : a (a -4) - a + 4
Factorize using the grouping method:
x2 + y2 + x + y + 2xy
Factorise : x2 - (a - 3)x - 3a
Factorise : ab(c2 + d2) - a2cd - b2cd
factorise: a2 - 5a+ 6
factorise: 2a2 + 7a + 6
factorise: 5 + 7x - 6x2
factorise: 5x2 - 4xy - 12y2
factorise: b(c - d)2 + a(d - c) + 3(c - d)
Factorise the following by grouping the terms:
8x3 - 24x2y + 54xy2 -162y3
