Advertisements
Advertisements
प्रश्न
factorise: 1 - 3x - 3y - 4(x + y)2
योग
Advertisements
उत्तर
1 - 3x - 3y - 4(x + y)2
= 1 - 3(x + y) - 4(x + y)2
= 1 - 4(x + y) + (x + y) - 4(x + y)2
= 1[1 - 4(x + y)] + (x + y)[1 - 4(x + y)]
= [1 - 4x - 4y](1 + x + y)
shaalaa.com
Factorisation by Grouping
क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
APPEARS IN
संबंधित प्रश्न
Factorise by the grouping method:
ab (x2 + 1) + x (a2 + b2)
Factorise : (a2 − b2) c + (b2 − c2)a
factorise: 5 + 3a - 14a2
factorise: (x - 2y)2 - 12(x - 2y) + 32
Factorise: 2(x + 2y)2 − 5(x + 2y) + 2
factorise: 12(a + b)2 - (a+ b) - 35
factorise: 15(5x - 4)2 - 10(5x - 4)
Factorise the following by grouping the terms:
15xy - 9x - 25y + 15
Factorise the following by grouping the terms:
15x2 + 7y - 3x - 35xy
Factorise the following by grouping the terms:
x + y + m(x + y)
