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प्रश्न
factorise: 1 - 3x - 3y - 4(x + y)2
योग
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उत्तर
1 - 3x - 3y - 4(x + y)2
= 1 - 3(x + y) - 4(x + y)2
= 1 - 4(x + y) + (x + y) - 4(x + y)2
= 1[1 - 4(x + y)] + (x + y)[1 - 4(x + y)]
= [1 - 4x - 4y](1 + x + y)
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Factorisation by Grouping
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