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सी.आई.एस.सी.ई.आईसीएसई ICSE Class 8

Factorise : (A2 - B2) C + (B2 - C2)A - Mathematics

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प्रश्न

Factorise : (a2 − b2) c + (b2 − c2)a 

योग
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उत्तर

(a2 − b2) c + (b2 − c2)a

Step 1: Write down the expression

(a2 − b2) c + (b2 − c2)a

Step 2: Use the difference of squares formula

x2 − y2 = (x − y)(x + y)

So,

a2 − b2 = (a − b)(a + b)

and 

b2 − c2 = (b − c)(b + c)

Substitute these into the given expression:

= (a − b)(a + b)c + (b − c)(b + c)a

Step 3: Expand both terms

= c(a2 − b2) + a(b2 − c2)

Simplify by removing brackets:

= a2c − b2c + ab2 − ac2

Step 4: Group terms for common factors

Group as:

= (a2c − ac2) + (ab2 − b2c)

Step 5: Factor each group

From the first group, factor out a c:

ac(a − c)

From the second group, factor out b2:

b2(a − c)

Now the expression becomes: 

= ac(a − c) + b2(a − c)

Step 6: Factor out the common term (a−c)

= (a − c)(ac + b2)

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Factorisation by Grouping
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 13: Factorisation - Exercise 13 (B) [पृष्ठ १५८]

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सेलिना Concise Mathematics [English] Class 8 ICSE
अध्याय 13 Factorisation
Exercise 13 (B) | Q 15 | पृष्ठ १५८
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